刚好有这个类似的代码，给你一个。
据我了解，这个最好用Servlet来实现，如果用JSP来做，你无法完全使用request.getOutputStream得到的流，因为JSP也要使用。这样就会出现一些不可预知的错误。
别外一个，楼主要的实际上就是传递一个文件，实际上与XML没有多大的关系。
package cn.webapp.servlet;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.commons.io.IOUtils;
import org.apache.commons.logging.Log;
import org.apache.commons.logging.LogFactory;
import cn.webapp.action.CatchImageAction;
/**
* ImageServlet
*
*
* @web.servlet name="FileServlet"
* @web.servlet-mapping url-pattern="/fileServlet"
*
*
* http://localhost:8080/xxxx/fileServlet?fileName=abc.wav
*
* @author <a mailto=kfuly-code06@yahoo.com.cn> lilao</a>
*/
public class FileServlet extends HttpServlet {
Log log = LogFactory.getLog(FileServlet.class);
/**
* when get image from file��will find this file from web app root
*/
public static final String FILE_NAME = "fileName";
public static String PROXY_SERVER_IP = "192.168.10.142";
public static String RELATIVE_PATH="/images";
/**
* This servlet makes a connection to the HTTP Server.
*
* @param request
* the HTTP request object
* @param response
* the HTTP response object
* @throws IOException
* thrown when there is a problem getting the writer
*/
protected void doGet(HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException {
// request.getSession().getValue("user");
String fileName = null;
fileName = request.getParameter(FILE_NAME);
try {
outSocket(response.getOutputStream(), fileName);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
/**
* out the content of file to out stream
*
* @param out
* @param file
* @return this size which have bean return
*/
private void outSocket(OutputStream out, String fileName) throws Exception {
String absolutePath=RELATIVE_PATH+"/"+fileName;
InputStream fis = new FileInputStream(this.getServletContext()
.getRealPath(absolutePath));
IOUtils.copy(fis, out);
out.flush();
out.close();
fis.close();
}
}
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2006/6/26 10:35:00
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在JAVA中如何向一个指定的URL发送XML文件流？
